C++中string.find()函数与string::npos

先说说string::npos参数: npos 是一个常数,用来表示不存在的位置,类型一般是std::container_type::size_type 许多容器都提供这个东西。取值由实现决定,一般是-1,这样做,就不会存在移植的问题了。 再来说说find函数: fin
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python——unpack问题 ocr_recognize timeout , exception:unpack requires a string argument of length 46

rObjBuff = "".join(unpack('=%ds' % ObjLen, recv_buf[6+i*ObjLen:6+(i+1)*ObjLen]))score, bbox1, bbox2, bbox3, bbox4, p00, p01, p10, p11, p20, p21, p30,
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Swift - 将String类型的数字转换成数字类型(支持十进制、十六进制)

1,十进制的字符串转成数字Swift中,如果要把字符串转换成数字类型(比如整型,浮点型等)。可以先转成NSString类型,让后再转。1234//将文本框中的值转换成数字var i = (tf1.text as NSString).intValuevar f = (tf1.text as NSStr
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SVN遇到Can't convert string from 'UTF-8' to native encoding(转)

svn: Can't convert string from 'UTF-8' to native encoding:svn: platform/console-framework/portal/img/zhanzhang_logo - ?\226?\148?\130?\206?\149.png这明显
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优雅的将Map转为String工具类

import com.alibaba.fastjson.JSONObject;import org.apache.commons.lang3.StringUtils;import java.util.ArrayList;import java.util.List;import java.util.M
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[LeetCode] Delete Operation for Two Strings 两个字符串的删除操作

 Given two words word1 and word2, find the minimum number of steps required to make word1 and word2 the same,
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scramble-string——两个字符串经过树化并旋转后是否一致、递归、动态规划

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively.Below is one possible represen
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Interleaving String——是否由两个string交叉、DP

Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.For example,Given:s1 = 
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[LeetCode] Add Bold Tag in String 字符串中增添加粗标签

 Given a string s and a list of strings dict, you need to add a closed pair of bold tag <b> and </b>&nb
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【转】Uint8Array 转为 string,解决中文乱码

来源: <http://stackoverflow.com/questions/8936984/uint8array-to-string-in-javascript/22373197>/* utf.js - UTF-8 <=> UTF-16 convertion * * Co
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