prometheus 结合 kubernetes时,提示User cannot list services at the cluster scope.如何解决?

这表示认证这一阶段已通过,赋权未到位。但kube-prometheus是一体化,全家桶安装,我试过几次自定义clusterRole,binding,都解决不完全。于是来个快刀。  搞定。kubectl create clusterrolebinding myname-cluste
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【转】计算Java List中的重复项出现次数

本文演示如何使用Collections.frequency和Map来计算重复项出现的次数。(Collections.frequency在JDK 1.5版本以后支持) [java] view plain copy package com.qiyaden
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list数组归并去重

C#两路list数组归并去重个相同类型已排序数据进行合并,虽然list数组中有AddRange方法,但它只是把第二个数组从第一个数组末尾插入,假如两个数组有重复数据,保存进去。还有Union方法合并去重,首先会从第一个数组进行检查然后再把第二个数组数据从第一个数组依次从末尾插入,但相对于自定义类型排
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JAVA8-让代码更优雅之List排序

先定义一个实体类@Data@AllArgsConstructor@NoArgsConstructorpublic class Human { private String name; private int age; }下面的操作都基于这个类来进行操作。这里面使用了Lombok类库
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[React] Create a Virtualized List with Auto Sizing Cells using react-virtualized and CellMeasurer

In this lesson we'll use CellMeasurer and CellMeasurerCache to automatically calculate and cache the height of a row. This will al
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[React] Create an Auto Resizing Virtualized List with react-virtualized

In this lesson we'll show how to use the AutoSizer component from react-virtualized to automatically measure the width/height of o
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remove-duplicates-from-sorted-list I&II——去除链表中重复项

I、Given a sorted linked list, delete all duplicates such that each element appear only once.For example,Given1->1->2, return1->2.Given1-
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【LeetCode】Partition List ——链表排序问题

【题目】 Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to&nb
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Convert Sorted List to Binary Search Tree——将链表转换为平衡二叉搜索树 &&convert-sorted-array-to-binary-search-tree——将数列转换为bst

Convert Sorted List to Binary Search TreeGiven a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
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linked-list-cycle-ii——链表,找出开始循环节点

Given a linked list, return the node where the cycle begins. If there is no cycle, returnnull.Follow up:Can you solve it without using extra space?&nb
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