POJ 1269 Intersecting Lines

直线求交,我的方法是叉积为0联立解方程。#include<iostream>#include<cstdio>#include<cstring>#include<algorithm>#include<cmath>#define maxn 10
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【SPFA+二分答案】BZOJ1614- [Usaco2007 Jan]Telephone Lines架设电话线

沉迷于刷水以前的那个二分写法过不了QAQ 换了一种好像大家都比较常用的二分。原因还不是很清楚。【题目大意】给出一张图,可以将其中k条边的边权减为0,求1到n的路径中最长边的最小值。【思路】二分答案,即最长边的最小值x。对于每次check(x),我们将边权大于x的边设为1,边权小于等于x的边设为0,跑
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Walkthrough: Arranging Controls on Windows Forms Using Snaplines

https://msdn.microsoft.com/en-us/library/t5b5kc41(v=vs.110).aspxSpacing and Aligning Controls Using SnaplinesSnaplines give you an accurate and intuit
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SmartSVN提示 svn: File has inconsistent newlines 解决

用SmartSVN提交代码的时候提示:svn: File has inconsistent newlines本文转自:http://www.youduoshao.com/2014-10-05/201410052335.html这是由于要提交的文件编码时混合了windows和unix符号导致的。解决方
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POJ 1269 - Intersecting Lines 直线与直线相交

题意:    判断直线间位置关系: 相交,平行,重合  1 include <iostream> 2 #include <cstdio> 3 using namespace std; 4 struct Point 5 { 6 i
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UVALive - 6955 Finding Lines 随机算法

题目链接:http://acm.hust.edu.cn/vjudge/contest/126968#problem/F题意给你n个点,问是否有>=p/100*n个点共线(p>=20&&p<=100)。题解随机枚举两个点,判过这两条直线的点是否满足要求。代码#incl
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POJ 1269 Intersecting Lines【判断直线相交】

题意:给两条直线,判断相交,重合或者平行思路:判断重合可以用叉积,平行用斜率,其他情况即为相交。求交点:这里也用到叉积的原理。假设交点为p0(x0,y0)。则有:(p1-p0)X(p2-p0)=0(p3-p0)X(p2-p0)=0展开后即是(y1-y2)x0+(x2-x1)y0+x1y2-x2y1=
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outdated: 21.Lines, Antialiasing, Timing, Ortho View And Simple Sounds

这是一个简单的小游戏,类型相当于amidar,不过也有1000行,手困眼花......UP\DOWN\LEFT\RIGHT控制,SPACE重新开始。在TimerInit()函数中,QueryPerformanceFrequency()函数查询性能计数器的频率。QueryPerformanceCoun
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BZOJ_1614_ [Usaco2007_Jan]_Telephone_Lines_架设电话线_(二分+最短路_Dijkstra/Spfa)

描述http://www.lydsy.com/JudgeOnline/problem.php?id=1614 分析类似POJ_3662_Telephone_Lines_(二分+最短路) Dijkstra: 1 #include <bits/stdc++.h> 2 us
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Counting Lines, Words, and Characters with wc

  Counting Lines, Words, and Characters with wc   When working with text files, you sometimes get a large amount of output. Before deci
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