[React] Close the menu component when click outside the menu

Most of the time, your components respond to events that occur within the component tree by defining their own handler or by accepting a handler defin
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[React] Style a React component with styled-components

In this lesson, we remove the mapping between a React component and the styles applied to it via classnames. We write our styles directly within the c
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[React Intl] Use a react-intl Higher Order Component to format messages

In some cases, you might need to pass a string from your intl messages.js file as a prop to a component. Instead of using react-intl&nb
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[Nuxt] Build a Navigation Component in Vue.js and Use in a Nuxt Layout

You can isolate parts of templates you want to re-use into components, but you can also reuse those components across pages using layouts. This lesson
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ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) D

Moriarty has trapped n people in n distinct rooms in a hotel. Some rooms are locked, others are unlocked. But, there is a conditio
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ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) C

Molly Hooper has n different kinds of chemicals arranged in a line. Each of the chemicals has an affection value, The i-th of them has
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ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) B

Sherlock has a new girlfriend (so unlike him!). Valentine's day is coming and he wants to gift her some jewelry.He bought n pieces of jewelr
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ICM Technex 2017 and Codeforces Round #400 (Div. 1 + Div. 2, combined) A

Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers of deduction, he came to kn
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spring cloud报错解决:java.lang.ClassNotFoundException: com.netflix.servo.monitor.Monitors

见鬼的事发生了。在家里电脑上拿样例代码,运行时OK的。但一到公司电脑,用同样的代码,就会报下面的错误=====================Caused by: java.lang.ClassNotFoundException: com.netflix.servo.monitor.Monitors
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BZOJ2240 : ural1676 Mortal Combat

首先如果最大匹配不足$n$个那么显然每条边都不可能在匹配为$n$的方案中。对于一条边$(u,v)$,如果它可能在最大匹配中,有两种情况:$1.(u,v)$是当前方案的匹配边。$2.$可以沿着$(u,v)$进行增广,那么在残余网络中$u$在$v$在一个环中,即属于同一个强连通分量。因为源点不存在出边,
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