如果会写但又要节省时间,你只要用这个方法就可以得到,金额的大写转换,祝你好运.  ,这里有两种发放,都是从网络上找的,我在这里总结一下。

//金额转大写

第一种方法       

   public static string chang1(decimal num)
        {
            string str1 = "零壹贰叁肆伍陆柒捌玖";            //0-9所对应的汉字
            string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; //数字位所对应的汉字
            string str3 = "";    //从原num值中取出的值
            string str4 = "";    //数字的字符串形式
            string str5 = "";  //人民币大写金额形式
            int i;    //循环变量
            int j;    //num的值乘以100的字符串长度
            string ch1 = "";    //数字的汉语读法
            string ch2 = "";    //数字位的汉字读法
            int nzero = 0;  //用来计算连续的零值是几个
            int temp;            //从原num值中取出的值

            num = Math.Round(Math.Abs(num), 2);    //将num取绝对值并四舍五入取2位小数
            str4 = ((long)(num * 100)).ToString();        //将num乘100并转换成字符串形式
            j = str4.Length;      //找出最高位
            if (j > 15) { return "溢出"; }
            str2 = str2.Substring(15 - j);   //取出对应位数的str2的值。如:200.55,j为5所以tr2=佰拾元角分

            //循环取出每一位需要转换的值
            for (i = 0; i < j; i++)
            {
                str3 = str4.Substring(i, 1);          //取出需转换的某一位的值
                temp = Convert.ToInt32(str3);      //转换为数字
                if (i != (j - 3) && i != (j - 7) && i != (j - 11) && i != (j - 15))
                {
                    //当所取位数不为元、万、亿、万亿上的数字时
                    if (str3 == "0")
                    {
                        ch1 = "";
                        ch2 = "";
                        nzero = nzero + 1;
                    }
                    else
                    {
                        if (str3 != "0" && nzero != 0)
                        {
                            ch1 = "零" + str1.Substring(temp * 1, 1);
                            ch2 = str2.Substring(i, 1);
                            nzero = 0;
                        }
                        else
                        {
                            ch1 = str1.Substring(temp * 1, 1);
                            ch2 = str2.Substring(i, 1);
                            nzero = 0;
                        }
                    }
                }
                else
                {
                    //该位是万亿,亿,万,元位等关键位
                    if (str3 != "0" && nzero != 0)
                    {
                        ch1 = "零" + str1.Substring(temp * 1, 1);
                        ch2 = str2.Substring(i, 1);
                        nzero = 0;
                    }
                    else
                    {
                        if (str3 != "0" && nzero == 0)
                        {
                            ch1 = str1.Substring(temp * 1, 1);
                            ch2 = str2.Substring(i, 1);
                            nzero = 0;
                        }
                        else
                        {
                            if (str3 == "0" && nzero >= 3)
                            {
                                ch1 = "";
                                ch2 = "";
                                nzero = nzero + 1;
                            }
                            else
                            {
                                if (j >= 11)
                                {
                                    ch1 = "";
                                    nzero = nzero + 1;
                                }
                                else
                                {
                                    ch1 = "";
                                    ch2 = str2.Substring(i, 1);
                                    nzero = nzero + 1;
                                }
                            }
                        }
                    }
                }
                if (i == (j - 11) || i == (j - 3))
                {
                    //如果该位是亿位或元位,则必须写上
                    ch2 = str2.Substring(i, 1);
                }
                str5 = str5 + ch1 + ch2;

                if (i == j - 1 && str3 == "0")
                {
                    //最后一位(分)为0时,加上“整”
                    str5 = str5 + '整';
                }
            }
            if (num == 0)
            {
                str5 = "零元整";
            }
            return str5;
        }

 

第二种方法

public string chang2(string money)
        {
            //将小写金额转换成大写金额          
            double MyNumber = Convert.ToDouble(money);
            String[] MyScale = { "分", "角", "元", "拾", "佰", "仟", "万", "拾", "佰", "仟", "亿", "拾", "佰", "仟", "兆", "拾", "佰", "仟" };
            String[] MyBase = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖" };
            String M = "";
            bool isPoint = false;
            if (money.IndexOf(".") != -1)
            {
                money = money.Remove(money.IndexOf("."), 1);
                isPoint = true;
            }
            for (int i = money.Length; i > 0; i--)
            {
                int MyData = Convert.ToInt16(money[money.Length - i].ToString());
                M += MyBase[MyData];
                if (isPoint == true)
                {
                    M += MyScale[i - 1];
                }
                else
                {
                    M += MyScale[i + 1];
                }
            }
            return M;
        }